This page provides comprehensive Class 11 Maths Exemplar Chapter 1 Exercise 1.1 Solutions. Detailed step-by-step solutions for Class 11 Maths NCERT Exemplar Chapter 1 Sets Exercise 1.1. Free PDF download and interactive practice.
Exercise 1.1
NCERT Exemplar Class 11 - Sets (MCQs)
Q1
Suppose \(A_1, A_2, \dots, A_{30}\) are thirty sets each having 5 elements and \(B_1, B_2, \dots, B_n\) are \(n\) sets each with 3 elements, let \(\bigcup_{i=1}^{30} A_i = \bigcup_{j=1}^{n} B_j = S\) and each element of \(S\) belongs to exactly 10 of the \(A_i\)'s and exactly 9 of the \(B_j\)'s. Then \(n\) is equal to
Let \(n(S)\) be the number of elements in \(S\).
Since each element of \(S\) is in exactly 10 of the \(A_i\)'s, we have \(10 \cdot n(S) = \sum n(A_i) = 30 \times 5 = 150\).
So, \(n(S) = 15\).
Since each element of \(S\) is in exactly 9 of the \(B_j\)'s, we have \(9 \cdot n(S) = \sum n(B_j) = n \times 3 = 3n\).
Substitute \(n(S) = 15\): \(9 \times 15 = 3n\).
\(135 = 3n \implies n = 45\).
$(c)$
Q2
Two finite sets have \(m\) and \(n\) elements. The number of subsets of the first set is 112 more than that of the second set. The values of \(m\) and \(n\) are, respectively
The set \((A \cap B')' \cup (B \cap C)\) is equal to
Using De Morgan's Law: \((A \cap B')' = A' \cup (B')' = A' \cup B\).
So the expression becomes \((A' \cup B) \cup (B \cap C)\).
Since \((B \cap C) \subset B\), the union with \(B\) absorbs it.
\(A' \cup B \cup (B \cap C) = A' \cup B\).
$(b)$
Q4
Let \(F_1\) be the set of parallelograms, \(F_2\) the set of rectangles, \(F_3\) the set of rhombuses, \(F_4\) the set of squares and \(F_5\) the set of trapeziums in the plane. Then \(F_1\) may be equal to
\(F_1\) (parallelograms) includes \(F_2\) (rectangles), \(F_3\) (rhombuses), and \(F_4\) (squares).
The union \(F_2 \cup F_3 \cup F_4 \cup F_1\) is simply \(F_1\).
$(d)$
Q5
Let \(S =\) set of points inside the square, \(T =\) set of points inside the triangle and \(C =\) set of points inside the circle. If the triangle and circle intersect each other and are contained in a square. Then
Since the triangle (T) and circle (C) are contained in the square (S), we have \(T \subset S\) and \(C \subset S\).
Therefore, the union of all three sets is just the largest set, \(S\).
$(c)$
Q6
If \(R\) be the set of points inside a rectangle of sides \(a\) and \(b\) (\(a, b > 1\)) with two sides along the positive direction of \(x\)-axis and \(y\)-axis. Then
The set of points *inside* a rectangle does not include the boundary.
Therefore, strict inequalities (\(<\)) are used.
\(R = \{(x, y) : 0 < x < a, 0 < y < b\}\).
$(d)$
Q7
In a class of 60 students, 25 students play cricket and 20 students play tennis, and 10 students play both the games. Then, the number of students who play neither is
Let \(C\) be cricket players, \(T\) be tennis players.