Let \(E, M, S\) denote the sets of students passing in English, Mathematics, and Science respectively.
Given: \(n(U)=100, n(E)=15, n(M)=12, n(S)=8\).
\(n(E \cap M)=6, n(M \cap S)=7, n(E \cap S)=4, n(E \cap M \cap S)=4\).
(i) \(n(E \cap M) - n(E \cap M \cap S) = 6 - 4 = 2\).
(ii) \(n(M \cap S) - n(E \cap M \cap S) = 7 - 4 = 3\).
(iii) \(n(M \text{ only}) = n(M) - n(M \cap E) - n(M \cap S) + n(E \cap M \cap S) = 12 - 6 - 7 + 4 = 3\).
(iv) More than one subject = (Exactly 2) + (Exactly 3).
Exactly 2: \((6-4) + (7-4) + (4-4) = 2 + 3 + 0 = 5\).
Exactly 3: 4.
Total = \(5 + 4 = 9\).
$(i) 2
(ii) 3
(iii) 3
(iv) 9$