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Question 1: Is zero a rational number? Can you write it in the form $p/q$, where $p$ and $q$ are integers and $q \neq 0$?
Solution:
Yes, zero is a rational number.
It can be written in the form $\frac{p}{q}$ as $\frac{0}{1}, \frac{0}{2}, \frac{0}{-5}$, etc., where the numerator $p=0$ is an integer and the denominator $q \neq 0$ is an integer. -
Question 2: Find six rational numbers between 3 and 4.
Solution:
To find 6 rational numbers, we multiply and divide 3 and 4 by $6+1=7$.
$3 = \frac{3 \times 7}{7} = \frac{21}{7}$ and $4 = \frac{4 \times 7}{7} = \frac{28}{7}$.
The six rational numbers are: $\frac{22}{7}, \frac{23}{7}, \frac{24}{7}, \frac{25}{7}, \frac{26}{7}, \frac{27}{7}$. -
Question 3: Locate $\sqrt{2}$ on the number line.
Solution:
1. Draw a number line and mark point O at 0 and A at 1.
2. At A, draw a perpendicular unit length AB = 1 unit.
3. Join OB. By Pythagoras theorem, $OB^2 = OA^2 + AB^2 = 1^2 + 1^2 = 2 \Rightarrow OB = \sqrt{2}$.
4. With O as center and radius OB, draw an arc cutting the number line at P. Point P represents $\sqrt{2}$. -
Question 4: Express $0.4\overline{7}$ in the form $p/q$.
Solution:
Let $x = 0.4777\dots$ (i)
Multiply by 10: $10x = 4.777\dots$ (ii)
Multiply by 100: $100x = 47.777\dots$ (iii)
Subtract (ii) from (iii): $90x = 43 \Rightarrow x = \frac{43}{90}$. -
Question 5: Rationalize the denominator of $\frac{1}{\sqrt{7}}$.
Solution: $\frac{1}{\sqrt{7}} \times \frac{\sqrt{7}}{\sqrt{7}} = \frac{\sqrt{7}}{7}$.
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Question 6: Find the decimal expansion of $\frac{10}{3}$.
Solution: Dividing 10 by 3 gives $3.333\dots$. It is a non-terminating repeating decimal ($3.\overline{3}$).
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Question 7: Is $\pi$ (pi) rational or irrational?
Solution: $\pi$ is an irrational number because its decimal expansion is non-terminating and non-recurring.
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Question 8: Simplify: $(\sqrt{5} + \sqrt{2})^2$.
Solution: Using $(a+b)^2 = a^2 + b^2 + 2ab$:
$(\sqrt{5})^2 + (\sqrt{2})^2 + 2(\sqrt{5})(\sqrt{2}) = 5 + 2 + 2\sqrt{10} = 7 + 2\sqrt{10}$. -
Question 9: Find the value of $(64)^{1/2}$.
Solution: $(64)^{1/2} = (8^2)^{1/2} = 8^{2 \times \frac{1}{2}} = 8^1 = 8$.
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Question 10: Write the rationalizing factor of $\frac{1}{\sqrt{2}}$.
Solution: The rationalizing factor is $\sqrt{2}$ (since $\sqrt{2} \times \sqrt{2} = 2$, which is rational).