Problem Solving Data Analysis⚡ High Yield (1-3 Questions per Test)
Mean Median Mode
Digital SAT Math Preparation & Desmos Strategies
4 Concepts20 Practice Qs30 Mock Qs⚡ Desmos Speed Hacks
Key Concepts & Worked Archetypes
Concept 1
Concept 1: The Arithmetic Mean
The mean is the sum of all values divided by the total count of values.
Sum of values: $\text{Sum} = \text{Mean} \times n$
Effect of adding a constant $k$ to every term: $\text{New Mean} = \text{Old Mean} + k$
Effect of multiplying every term by $k$: $\text{New Mean} = \text{Old Mean} \times k$
📘 Traditional Algebraic Method
Sum the data points and divide by the number of entries $n$.
⚡ SAT Speed Trick & Desmos Hack
Use the Desmos 'mean()' function by typing the list into a variable, e.g., L = [x1, x2, x3], then typing mean(L).
💡 Worked SAT Archetype Example
Problem: The mean of 5 numbers is 12. If a 6th number, 18, is added, what is the new mean?
📘 Step-by-Step Textbook Solution:
Step 1
Calculate the original sum: $5 \times 12 = 60$
Step 2
Add the new number to the sum: $60 + 18 = 78$
Step 3
Divide by the new count: $78 / 6 = 13$
Step 4
The new mean is 13.
⚡ Speed / Desmos Tactic:
Step 1
Define list L = [12, 12, 12, 12, 12, 18]
Step 2
Type mean(L) in a new line
Step 3
Read result 13
Concept 2
Concept 2: Median and Ordering
The median is the middle value of a data set when ordered from least to greatest.
For odd $n$: $\text{Median} = \text{value at position } (n+1)/2$
For even $n$: $\text{Median} = \text{average of values at } n/2 \text{ and } (n/2)+1$
The median is resistant to outliers, unlike the mean.
📘 Traditional Algebraic Method
Sort the data set in ascending order and identify the middle term.
⚡ SAT Speed Trick & Desmos Hack
Use the Desmos 'median()' function on a defined list.
💡 Worked SAT Archetype Example
Problem: Find the median of the set: {15, 3, 8, 12, 20, 5}.
📘 Step-by-Step Textbook Solution:
Step 1
Sort the set: {3, 5, 8, 12, 15, 20}
Step 2
Identify the two middle terms: 8 and 12
Step 3
Calculate the average: $(8 + 12) / 2 = 10$
Step 4
The median is 10.
⚡ Speed / Desmos Tactic:
Step 1
Define list L = [15, 3, 8, 12, 20, 5]
Step 2
Type median(L) in a new line
Step 3
Read result 10
Concept 3
Concept 3: Mode and Frequency
The mode is the value that appears most frequently in a data set.
A set can have one mode, multiple modes (multimodal), or no mode.
If all values appear with the same frequency, there is no mode.
The mode is the peak of a frequency histogram.
📘 Traditional Algebraic Method
Create a frequency table to count occurrences of each value.
⚡ SAT Speed Trick & Desmos Hack
Use the 'dotplot' or 'histogram' visualization in Desmos if data is provided in a table.
💡 Worked SAT Archetype Example
Problem: Find the mode of: {4, 7, 4, 9, 7, 4, 2}.
📘 Step-by-Step Textbook Solution:
Step 1
Count occurrences of 4: 3 times
Step 2
Count occurrences of 7: 2 times
Step 3
Count occurrences of 9: 1 time
Step 4
The value with the highest count is 4.
⚡ Speed / Desmos Tactic:
Step 1
Define list L = [4, 7, 4, 9, 7, 4, 2]
Step 2
Use the sort function to group values: sort(L)
Step 3
Observe the most frequent value is 4
Concept 4
Concept 4: Mean vs Median Sensitivity
The mean is sensitive to extreme values (outliers), while the median is robust.
If the distribution is skewed right, $\text{Mean} > \text{Median}$
If the distribution is skewed left, $\text{Mean} < \text{Median}$
If the distribution is symmetric, $\text{Mean} \approx \text{Median}$
📘 Traditional Algebraic Method
Compare the impact of adding a large value to the mean versus the median.
⚡ SAT Speed Trick & Desmos Hack
Test with a small set: {1, 2, 3} vs {1, 2, 100}.
💡 Worked SAT Archetype Example
Problem: Which measure changes more when an outlier is added to a set?
📘 Step-by-Step Textbook Solution:
Step 1
Original set {1, 2, 3}: Mean = 2, Median = 2
Step 2
Add outlier 100: {1, 2, 3, 100}
Step 3
New Mean: $106 / 4 = 26.5$
Step 4
New Median: $(2 + 3) / 2 = 2.5$
Step 5
The mean changed by 24.5, while the median changed by 0.5.
⚡ Speed / Desmos Tactic:
Step 1
Define L1 = [1, 2, 3]
Step 2
Define L2 = [1, 2, 3, 100]
Step 3
Compare mean(L1), mean(L2) and median(L1), median(L2)
Practice Questions (20)
Question 1Basic Calculation
Easy
The set of numbers $\{4, 8, 12, 16, 20\}$ represents the number of items sold by a store over 5 days. What is the mean of this set?
Hint: The mean is the sum of all values divided by the number of values.
📘 Step-by-Step Algebraic Solution
Step 1
Sum the values: $4 + 8 + 12 + 16 + 20 = 60$
Step 2
Divide by the count of numbers: $60 / 5$
Step 3
Result: $12$
⚡ Desmos Shortcut / Speed Hack
Step 1
Observe the set is an arithmetic sequence.
Step 2
For an arithmetic sequence, the mean equals the median.
Step 3
The middle number is 12.
Question 2Basic Calculation
Easy
What is the median of the data set $\{15, 22, 15, 30, 18\}$?
Hint: Order the numbers from least to greatest first.
📘 Step-by-Step Algebraic Solution
Step 1
Sort the list: $15, 15, 18, 22, 30$
Step 2
Identify the middle value in the sorted list.
Step 3
The middle value is $18$.
⚡ Desmos Shortcut / Speed Hack
Step 1
Type 'median([15, 22, 15, 30, 18])' into Desmos.
Step 2
Read the output.
Question 3Basic Calculation
Medium
A data set consists of 6 numbers. If the sum of the numbers is 150 and the mean is 25, what is the value of the 6th number if the sum of the first 5 numbers is 120?
Hint: The total sum is the mean multiplied by the count.
📘 Step-by-Step Algebraic Solution
Step 1
Total sum = $150$
Step 2
Sum of first 5 = $120$
Step 3
6th number = $150 - 120 = 30$
⚡ Desmos Shortcut / Speed Hack
Step 1
Recognize that the mean of 25 for 6 numbers implies a total of $6 \times 25 = 150$.
Step 2
Subtract the known sum from the total: $150 - 120 = 30$.
Question 4Basic Calculation
Medium
The mode of a set of 7 integers is 10. If the set is $\{8, 10, 12, x, 10, 15, 9\}$, what must be true about $x$?
Hint: The mode is the most frequent number. If 10 is the mode, it must appear more than any other number.
📘 Step-by-Step Algebraic Solution
Step 1
Count current frequencies: 10 appears twice, others appear once.
Step 2
To keep 10 as the mode, $x$ cannot create a new mode.
Step 3
If $x = 10$, the mode is still 10. If $x \neq 10$, the mode is still 10.
Step 4
Actually, $x$ can be anything, but the question implies $x$ is not 10 to maintain the current set structure.
⚡ Desmos Shortcut / Speed Hack
Step 1
Check the options.
Step 2
If $x=10$, 10 appears 3 times. If $x=5$, 10 appears 2 times. Both keep 10 as the mode.
Step 3
The most restrictive condition is $x \neq 10$ is not required, but $x$ cannot be a number that appears twice.
Question 5Basic Calculation
Hard
A set of 5 positive integers has a mean of 10, a median of 11, and a mode of 12. What is the smallest possible value for the smallest integer in the set?
Hint: Let the set be $a, b, 11, 12, 12$. The sum must be 50.
📘 Step-by-Step Algebraic Solution
Step 1
Set is $a, b, 11, 12, 12$.
Step 2
Sum: $a + b + 11 + 12 + 12 = 50$.
Step 3
$a + b = 15$.
Step 4
To minimize $a$, maximize $b$. Since median is 11, $b \leq 11$.
Step 5
If $b = 11$, $a = 4$. If $b = 12$, median would change. So $b=11, a=4$. Wait, check constraints.
Step 6
Smallest $a$ is 3 if $b=12$ (but mode is 12, so $b$ can be 12).
⚡ Desmos Shortcut / Speed Hack
Step 1
Sum is 50.
Step 2
$a + b + 11 + 12 + 12 = 50 \implies a + b = 15$.
Step 3
Since $b \leq 11$, $a \geq 4$. If $b=12$, $a=3$.
Question 6Missing Value Algebra
Easy
The mean of $\{5, 10, x, 20\}$ is 12. What is the value of $x$?
Hint: Sum divided by 4 equals 12.
📘 Step-by-Step Algebraic Solution
Step 1
$(5 + 10 + x + 20) / 4 = 12$
Step 2
$35 + x = 48$
Step 3
$x = 13$
⚡ Desmos Shortcut / Speed Hack
Step 1
Total sum must be $4 \times 12 = 48$.
Step 2
$48 - (5 + 10 + 20) = 13$.
Question 7Missing Value Algebra
Easy
If the median of $\{2, 5, x, 10, 12\}$ is 7, what is $x$?
Hint: The median is the middle number when sorted.
If the median of $\{2, 5, 8, x, 15\}$ is 7, what is $x$?
Explanation:
Step 1
Ordered set must have 7 as the middle element.
Step 2
$2, 5, x, 8, 15$.
Step 3
For 7 to be the median, $x$ must be 7.
Question 18Level 2: Target 700+
The average of 5 consecutive integers is 10. What is the largest integer?
Explanation:
Step 1
Let the integers be $n-2, n-1, n, n+1, n+2$.
Step 2
The mean is $n = 10$.
Step 3
The largest integer is $n+2 = 12$.
Question 19Level 2: Target 700+
If the mean of $x, x+2, x+4$ is 10, what is the median?
Explanation:
Step 1
$(x + x+2 + x+4) / 3 = 10$.
Step 2
$3x + 6 = 30 \implies 3x = 24 \implies x = 8$.
Step 3
The set is $8, 10, 12$. The median is 10.
Question 20Level 2: Target 700+
A set has 4 numbers. The mean is 10 and the range is 8. If the smallest number is 6, what is the largest?
Explanation:
Step 1
Range = Max - Min.
Step 2
$8 = \text{Max} - 6$.
Step 3
$\text{Max} = 14$.
Question 21Level 3: 800 Mastery
A set of 10 integers has a mean of 10.5. If the sum of the 5 smallest integers is 20, what is the maximum possible value of one of the 5 largest integers?
Explanation:
Step 1
Total sum = $10 \times 10.5 = 105$.
Step 2
Sum of 5 largest = $105 - 20 = 85$.
Step 3
To maximize one, assume the other 4 are the smallest possible distinct integers (e.g., 0).
Step 4
$85 + 0 + 0 + 0 + 0 = 85$.
Question 22Level 3: 800 Mastery
The mean of a set of $n$ numbers is 20. If each number $x_i$ is replaced by $2x_i + 3$, what is the new mean?
Explanation:
Step 1
New mean = $2(\text{old mean}) + 3$.
Step 2
$2(20) + 3 = 43$.
Question 23Level 3: 800 Mastery
In a set of 7 numbers, the mean is 15 and the median is 15. If the 3 smallest numbers are 10, 11, 12, what is the maximum possible value of the largest number?
Explanation:
Step 1
Total sum = $7 \times 15 = 105$.
Step 2
Known sum = $10 + 11 + 12 + 15 = 48$.
Step 3
Remaining sum for 3 numbers (including largest) = $105 - 48 = 57$.
Step 4
To maximize the largest, set the other two to the median (15).
Step 5
$57 - 15 - 15 = 27$.
Question 24Level 3: 800 Mastery
The mean of 5 numbers is 10. If the median is 12 and the mode is 15, what is the smallest possible value for the smallest number?
Explanation:
Step 1
Set is $a, b, 12, 15, 15$.
Step 2
Sum = $a + b + 12 + 15 + 15 = 50 \implies a + b = 8$.
Step 3
To minimize $a$, maximize $b$. Since $b \le 12$, let $b = 12$.
Step 4
$a + 12 = 8 \implies a = -4$. Wait, check constraints: $a \le b \le 12$. If $a=-5, b=13$ (No). If $a=-4, b=12$. Smallest is -4.
Question 25Level 3: 800 Mastery
A set of 4 numbers has a mean of 10 and a median of 10. If the range is 10, what is the set?
Explanation:
Step 1
Mean 10 means sum is 40.
Step 2
Median 10 means $(x_2 + x_3)/2 = 10$.
Step 3
Range 10 means $x_4 - x_1 = 10$.
Step 4
Test A: Sum=40, Median=(9+11)/2=10, Range=15-5=10. Matches.
Question 26Level 3: 800 Mastery
If the mean of $x_1, x_2, x_3, x_4$ is $M$, what is the mean of $x_1-k, x_2-k, x_3-k, x_4-k$?
Explanation:
Step 1
New sum = $(x_1-k) + (x_2-k) + (x_3-k) + (x_4-k) = (x_1+x_2+x_3+x_4) - 4k$.
Step 2
New mean = $(4M - 4k) / 4 = M - k$.
Question 27Level 3: 800 Mastery
The mean of 10 numbers is 20. If one number is replaced by 40, the new mean is 22. What was the original number?
Explanation:
Step 1
Old sum = 200. New sum = 220.
Step 2
Difference = 20.
Step 3
New number - Old number = 20. $40 - x = 20 \implies x = 20$.
Question 28Level 3: 800 Mastery
A set of 5 numbers has mean 10, median 10, and mode 10. If the numbers are integers and the range is 4, what is the set?
Explanation:
Step 1
Sum = 50.
Step 2
Median = 10, Mode = 10.
Step 3
Range = 4. $12 - 8 = 4$.
Step 4
$8 + 10 + 10 + 10 + 12 = 50$. Matches.
Question 29Level 3: 800 Mastery
If the mean of $a, b, c$ is 10 and the mean of $c, d, e$ is 20, what is the mean of $a, b, c, d, e$?
Explanation:
Step 1
$a+b+c = 30$.
Step 2
$c+d+e = 60$.
Step 3
$a+b+c+d+e = 90 - c$.
Step 4
Without knowing $c$, the mean $(90-c)/5$ cannot be determined.
Question 30Level 3: 800 Mastery
The mean of 5 numbers is 10. If we add a 6th number, the mean becomes 12. What is the 6th number?