Class 10 • Science • CBSE

Chemical Reactions and Equations

Chapter 1 • Comprehensive Concept & Practice Notes
Board Focus Quick Revision NCERT Based
Chemical Reactions and Equations
Master definitions, balanced chemical equations, reaction types, and oxidation-reduction concepts with clear explanations.
💡 Key Practice: Write the balanced chemical equation with state symbols and mention observations or color changes where required.

Concepts & Theories

NCERT-aligned comprehensive notes

01
What is a Chemical Reaction?
  • Definition: A process in which original substances lose their nature and identity to form new chemical substances with completely different properties.
  • Mechanism: Involves the breaking of old chemical bonds in reactants and the formation of new chemical bonds to yield products.
  • Key Rule: Atoms of one element do not change into another element; only a rearrangement of atoms takes place.
💡 Exam Point: If asked how you know a reaction occurred, state that a chemical change has taken place resulting in new products.
02
Signs of a Chemical Reaction
  • Change in State: e.g., Hydrogen (gas) + Oxygen (gas) → Water (liquid).
  • Change in Colour: e.g., Iron (grey) + Copper sulphate (blue) → Iron sulphate (pale green) + Copper (brown).
  • Evolution of a Gas: e.g., Zinc + Dilute Sulphuric acid → Zinc sulphate + Hydrogen gas (H₂ bubbles).
  • Change in Temperature: e.g., Quicklime + Water → Slaked lime + Heat (Exothermic).
  • Formation of a Precipitate: e.g., Lead nitrate + Potassium iodide → Lead iodide (Yellow precipitate).
🧠 Mnemonic: SCGTP = State • Colour • Gas • Temperature • Precipitate
03
Word Equation
  • Definition: A simplified representation of a chemical reaction using the names of the reactants and products.
  • Reactants: Substances that undergo chemical change (written on the Left-Hand Side).
  • Products: New substances formed during the reaction (written on the Right-Hand Side).
Magnesium + Oxygen → Magnesium oxide
(Reactants) → (Product)
✍️ Board Tip: An arrowhead (→) points towards the products, indicating the direction of the reaction. A plus sign (+) separates multiple reactants or products.
04
Chemical Equation
  • Definition: A representation of a chemical reaction using symbols and chemical formulae of the substances involved.
  • Skeletal Chemical Equation: An unbalanced equation where the number of atoms of each element is not equal on both sides.
  • Balanced Chemical Equation: An equation where the number of atoms of each element is exactly equal on both sides of the arrow.
Mg + O₂ → MgO
(Skeletal equation)

2Mg + O₂ → 2MgO
(Balanced equation)
⚠️ Rule: Never change the chemical formula (subscripts) while balancing. Only adjust the stoichiometric coefficients.
05
Law of Conservation of Mass
  • Statement: Mass can neither be created nor destroyed in a chemical reaction.
  • Implication for Equations: The total mass of the elements present in the products must be equal to the total mass of the elements present in the reactants.
  • Atomic Level: The number of atoms of each element remains the same, before and after a chemical reaction.
  • Why we balance equations: To strictly satisfy the Law of Conservation of Mass.
06
How to Balance an Equation
  • Method Used: Hit-and-trial method.
  • Step 1: Write Formulae: Write the correct skeletal equation and enclose formulae in boxes (do not alter anything inside the box).
  • Step 2: List Atoms: Count the number of atoms of each element on both LHS and RHS.
  • Step 3: Balance Maximum Atoms First: Start balancing with the compound that contains the maximum number of atoms (often Oxygen or Hydrogen).
  • Step 4: Balance Remaining: Adjust coefficients for other elements until LHS = RHS.
  • Step 5: Write State Symbols: Add (s), (l), (g), or (aq) to make the equation more informative.
3Fe + 4H₂O → Fe₃O₄ + 4H₂
⚠️ Common Mistake: Never turn H₂O into H₂O₄ to balance oxygen. Always put the coefficient in front (e.g., 4H₂O).
07
Physical State Symbols
  • Purpose: Used to make a chemical equation more informative regarding the physical states of reactants and products.
  • (s): Solid state (e.g., metals, precipitates).
  • (l): Liquid state (e.g., water, bromine).
  • (g): Gaseous state (e.g., hydrogen, oxygen, steam).
  • (aq): Aqueous solution (when a reactant or product is present as a solution in water).
3Fe(s) + 4H₂O(g) → Fe₃O₄(s) + 4H₂(g)
💡 Board Tip: Only include physical state symbols in your exam answers if specifically asked for, or to ensure maximum marks in 3/5 mark questions.

Types of Chemical Reactions

Very important for MCQs + 2/3 markers

Combination Reaction

  • Definition: Two or more reactants combine to form a single product.
CaO (s) + H₂O (l) → Ca(OH)₂ (aq) + Heat

💡 Board Application (Whitewashing): Slaked lime Ca(OH)₂ reacts with CO₂ in air to form a shiny layer of CaCO₃ on walls after 2–3 days.

Decomposition Reaction

  • Definition: A single reactant breaks down into two or more simpler products.
CaCO₃ (s) ──Heat──→ CaO (s) + CO₂ (g)

Requires Energy (Endothermic): Takes place via Thermal (Heat Δ), Electrolytic (Electricity), or Photolytic (Sunlight) decomposition.

Displacement Reaction

  • Definition: A more reactive element displaces a less reactive element from its solution.
Fe (s) + CuSO₄ (aq) → FeSO₄ (aq) + Cu (s)

💡 Board Observation: Blue CuSO₄ turns pale green FeSO₄; brown copper deposits on the iron nail.

Double Displacement

  • Definition: Mutual exchange of ions between two compounds forming an insoluble precipitate.
Na₂SO₄ (aq) + BaCl₂ (aq) → BaSO₄ (s)↓ + 2NaCl (aq)

💡 Precipitation: White BaSO₄↓ settles at bottom; Pb(NO₃)₂ + KI gives yellow PbI₂↓.

08
Exothermic vs Endothermic Reactions
  • Exothermic Reaction: Reactions in which heat is given out along with the formation of products. Temperature of the surroundings rises.
  • Endothermic Reaction: Reactions which require energy in the form of heat, light or electricity to break reactants. Temperature of the surroundings falls.
🔥 Top Board Exothermic Examples:
1. Respiration: Glucose is broken down with oxygen to release energy. (C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + Energy)
2. Burning of Natural Gas: CH₄ + 2O₂ → CO₂ + 2H₂O + Heat
3. Slaking of Quicklime: CaO (s) + H₂O (l) → Ca(OH)₂ (aq) + Heat
4. Decomposition of vegetable matter into compost.
❄️ Top Board Endothermic Examples:
1. Photosynthesis: Requires sunlight to convert CO₂ and water into glucose.
2. Thermal Decomposition: CaCO₃ + Heat → CaO + CO₂
09
Oxidation, Reduction & Agents
  • Oxidation: The addition of oxygen to a substance, OR the removal of hydrogen from a substance.
  • Reduction: The addition of hydrogen to a substance, OR the removal of oxygen from a substance.
  • Redox Reaction: A reaction in which one reactant gets oxidised while the other gets reduced simultaneously.
CuO + H₂ ──Heat──→ Cu + H₂O
(CuO is reduced to Cu; H₂ is oxidised to H₂O)
  • Oxidising Agent: The substance that gives oxygen (or removes hydrogen) for oxidation. It gets reduced itself. (e.g., CuO)
  • Reducing Agent: The substance that gives hydrogen (or removes oxygen) for reduction. It gets oxidised itself. (e.g., H₂)
🧠 OIL RIG: Oxidation Is Loss (of electrons); Reduction Is Gain.
10
Corrosion
  • Definition: The process in which metals are slowly eaten away by the action of air, moisture, or a chemical (such as an acid) on their surface.
  • Rusting of Iron: When iron is exposed to moist air for a long time, it acquires a coating of a brown flaky substance called rust. (Fe₂O₃·xH₂O)
  • Other Examples: Black coating on silver (Ag₂S) and the green coating on copper (Basic copper carbonate).
  • Prevention Methods: Painting, oiling, greasing, galvanisation (coating with zinc), chrome plating, anodising or making alloys.
11
Rancidity
  • Definition: The condition produced by aerial oxidation of fats and oils in foods marked by an unpleasant smell and taste.
  • Prevention Methods (Board Favorites):
🎯 Top 4 Prevention Methods:
1. Adding Antioxidants: Substances like BHA and BHT are added to foods containing fats and oils to prevent oxidation.
2. Flushing with Nitrogen Gas: Packaging fat/oil containing foods (like potato chips) in nitrogen gas to prevent oxygen contact.
3. Using Air-tight Containers: Storing food in air-tight containers slows down the oxidation process.
4. Refrigeration: Keeping food in the refrigerator lowers the temperature, slowing down the oxidation rate.

Crucial NCERT Lab Activities

30%+ of Board Exams test these exact observations

12
Must-Know NCERT Activity Observations
Activity & Reaction Observation / Test Board Question / Key Reason
Act 1.1: Burning Magnesium Ribbon
2Mg + O₂ → 2MgO
Dazzling white flame; white powder forms Why rub with sandpaper? Removes protective layer of basic magnesium carbonate from surface before ignition.
Act 1.2: Lead Nitrate + KI
Pb(NO₃)₂ + 2KI → PbI₂↓ + 2KNO₃
Bright Yellow precipitate forms instantly Double displacement and precipitation reaction. Precipitate is PbI₂.
Act 1.3: Zinc + Dilute H₂SO₄
Zn + H₂SO₄ → ZnSO₄ + H₂↑
Gas bubbles rise; flask gets hot (exothermic) Test for H₂ gas: Burns with a characteristic 'pop' sound when a burning splinter is brought near.
Act 1.5: Heating Ferrous Sulphate
2FeSO₄ ──Δ──→ Fe₂O₃ + SO₂↑ + SO₃↑
Green crystals turn white, then brown; choking smell of burning sulphur Thermal decomposition: FeSO₄·7H₂O loses water of crystallisation then decomposes into ferric oxide (Fe₂O₃) and gases SO₂, SO₃.
Act 1.6: Heating Lead Nitrate
2Pb(NO₃)₂ ──Δ──→ 2PbO + 4NO₂↑ + O₂↑
Brown fumes of NO₂ gas; yellow solid residue of PbO Thermal decomposition producing nitrogen dioxide gas (NO₂).
Act 1.7: Electrolysis of Water
2H₂O ──Electric──→ 2H₂↑ + O₂↑
Gas collected at cathode (H₂) is double the volume of anode (O₂) (2:1 ratio) Because a water molecule contains 2 hydrogen atoms for every 1 oxygen atom (H : O = 2 : 1).
Act 1.8: Silver Chloride in Sun
2AgCl ──Sunlight──→ 2Ag + Cl₂↑
White AgCl turns grey Photolytic decomposition; reaction is used in black-and-white photography.

Master Reaction Color & Gas Chart

Solve any "Identify Compound X" board problem in seconds

13
Quick Color Identification Key
Copper metal (Cu): Shiny reddish-brown
Copper Oxide (CuO): Black powder
Copper Sulphate solution (CuSO₄): Deep Blue
Ferrous Sulphate solution (FeSO₄): Pale Green
Ferric Oxide (Fe₂O₃): Reddish Brown
Barium Sulphate (BaSO₄): White precipitate
Lead Iodide (PbI₂): Yellow precipitate
Nitrogen Dioxide (NO₂): Brown fumes
Hydrogen gas (H₂): Colourless, burns with 'pop' sound
Carbon Dioxide (CO₂): Colourless, turns lime water milky
💡 Lime Water Test: Ca(OH)₂ (aq) + CO₂ (g) → CaCO₃↓ (white milky) + H₂O. On passing excess CO₂, milkiness disappears due to soluble Ca(HCO₃)₂.

Answering Strategy for Theory Questions

Standard structured format for 3 & 5 mark questions

Scientific Definition → Core Principle/Reason → Balanced Chemical Equation → Observation / Colour Change

When answering 3-mark and 5-mark descriptive questions, write concise, structured points: state the formal scientific definition, explain the underlying mechanism, provide the fully balanced chemical equation with physical state symbols, and record any observable color or temperature changes.

NCERT Exercises

Questions with step-by-step solutions

1. Which statements about 2PbO(s) + C(s) → 2Pb(s) + CO₂(g) are incorrect?
Answer
(a) Lead is getting reduced.
(b) Carbon dioxide is getting oxidised.
(c) Carbon is getting oxidised.
(d) Lead oxide is getting reduced.

Carbon gains oxygen to form CO₂, so carbon is oxidised. PbO loses oxygen and forms Pb, so PbO is reduced. Therefore, the incorrect statement is (b).

2. Fe₂O₃ + 2Al → Al₂O₃ + 2Fe is an example of which reaction?
Answer

Displacement reaction. Aluminium displaces iron from iron(III) oxide.

3. What happens when dilute hydrochloric acid is added to iron filings?
Answer

Hydrogen gas and iron chloride are produced.

Fe + 2HCl → FeCl₂ + H₂
4. What is a balanced chemical equation? Why should equations be balanced?
Board Answer

A balanced chemical equation has an equal number of atoms of each element on both sides.

Equations are balanced to obey the law of conservation of mass.

5. Translate and balance: Hydrogen gas combines with nitrogen to form ammonia.
Answer
N₂ + 3H₂ → 2NH₃
6. Balance the following: HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + H₂O
Answer
2HNO₃ + Ca(OH)₂ → Ca(NO₃)₂ + 2H₂O
7. Write and balance: Calcium hydroxide + Carbon dioxide → Calcium carbonate + Water
Answer
Ca(OH)₂ + CO₂ → CaCO₃ + H₂O
8. Identify the reaction type: Hydrogen + Chlorine → Hydrogen chloride.
Answer

It is a combination reaction because two reactants combine to form one product.

H₂ + Cl₂ → 2HCl
9. What are exothermic and endothermic reactions?
Answer

Exothermic: reactions in which heat is released.

Endothermic: reactions in which energy is absorbed.

Example of exothermic reaction: respiration.

10. Why is respiration considered an exothermic reaction?
Answer

During respiration, glucose reacts with oxygen and releases energy.

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + Energy
11. Why are decomposition reactions called the opposite of combination reactions?
Answer

In combination, two or more substances form a single product. In decomposition, one substance breaks into two or more products.

12. Write decomposition equations using heat, light and electricity.
Answer
CaCO₃ ──Heat──→ CaO + CO₂
2AgCl ──Sunlight──→ 2Ag + Cl₂
2H₂O ──Electricity──→ 2H₂ + O₂
13. Difference between displacement and double displacement.
Answer

Displacement: one element displaces another element from its compound.

Double displacement: ions/groups are exchanged between two compounds.

Fe + CuSO₄ → FeSO₄ + Cu
Na₂SO₄ + BaCl₂ → BaSO₄ + 2NaCl
14. Write the reaction involved in recovery of silver from silver nitrate using copper.
Answer
Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

Copper displaces silver from silver nitrate.

15. What is a precipitation reaction?
Answer

A reaction in which an insoluble solid is formed from solutions is called a precipitation reaction.

Na₂SO₄ + BaCl₂ → BaSO₄↓ + 2NaCl

BaSO₄ is the white insoluble precipitate.

16. Explain oxidation and reduction in terms of oxygen.
Answer

Oxidation: gain of oxygen.

Reduction: loss of oxygen.

2Cu + O₂ → 2CuO
17. A shiny brown element X becomes black on heating in air. Identify X and the black compound.
Answer

X = Copper (Cu)
Black compound = Copper(II) oxide (CuO)

2Cu + O₂ → 2CuO
18. Why is paint applied on iron articles?
Answer

Paint forms a protective layer and prevents iron from coming into contact with air and moisture, thereby reducing corrosion.

19. Why are oil- and fat-containing food items flushed with nitrogen?
Answer

Nitrogen reduces contact with oxygen and therefore slows oxidation of fats and oils, preventing rancidity.

20. Explain corrosion and rancidity with one example each.
Answer

Corrosion: gradual deterioration of a metal due to environmental substances. Example: rusting of iron.

Rancidity: oxidation of fats/oils causing unpleasant smell and taste.

PYQs

Board-style high-frequency questions • Reveal on demand

1 MARK | CBSE Recurring

What type of reaction occurs when a single substance breaks down into two or more products?

Answer

Decomposition reaction. A single reactant decomposes into two or more simpler products when energy is supplied in the form of heat, light, or electricity.

1 MARK | CBSE 2020, 2018

What is observed when copper powder is heated in air?

Answer

The brown surface of copper powder develops a black coating of copper(II) oxide ($CuO$) due to oxidation by oxygen in air.

2Cu (s) + O₂ (g) ──Heat──→ 2CuO (s) (Black)
2 MARKS | CBSE 2023, 2019

Explain why silver chloride ($AgCl$) turns grey when exposed to sunlight. Write the chemical equation.

Answer

White silver chloride decomposes into grey metallic silver ($Ag$) and yellowish-green chlorine gas ($Cl_2$) in the presence of sunlight (Photolytic Decomposition).

2AgCl (s) [White] ──Sunlight──→ 2Ag (s) [Grey] + Cl₂ (g)
2 MARKS | CBSE 2024, 2020

Why is the reaction between iron nails and copper sulphate solution called a displacement reaction? What colour change occurs?

Answer

Iron is more reactive than copper in the reactivity series, so it displaces copper from copper sulphate solution. The blue colour of $CuSO_4$ fades to light green (formation of $FeSO_4$) and a reddish-brown copper deposit forms on the iron nail.

Fe (s) + CuSO₄ (aq) [Blue] → FeSO₄ (aq) [Light Green] + Cu (s) [Reddish-Brown]
3 MARKS | CBSE 2023, 2017

Explain oxidation and reduction in terms of oxygen gain/loss using the reaction between copper(II) oxide and hydrogen.

Answer

Oxidation: Hydrogen ($H_2$) gains oxygen to form water ($H_2O$) $\implies$ $H_2$ is oxidised (and acts as the Reducing Agent).
Reduction: Copper(II) oxide ($CuO$) loses oxygen to form metallic copper ($Cu$) $\implies$ $CuO$ is reduced (and acts as the Oxidising Agent).

CuO + H₂ ──Heat──→ Cu + H₂O
3 MARKS | CBSE 2022, 2016

Differentiate between combination, decomposition, displacement, and double displacement reactions with one balanced equation each.

Answer

1. Combination Reaction: Two or more reactants combine to form a single product.
$$CaO (s) + H_2O (l) o Ca(OH)_2 (aq) + Heat$$

2. Decomposition Reaction: A single compound breaks down into two or more simpler substances.
$$CaCO_3 (s) \xr→{\Delta} CaO (s) + CO_2 (g)$$

3. Displacement Reaction: A more reactive element displaces a less reactive element from its compound.
$$Zn (s) + CuSO_4 (aq) o ZnSO_4 (aq) + Cu (s)$$

4. Double Displacement Reaction: Mutual exchange of ions between two compounds.
$$Na_2SO_4 (aq) + BaCl_2 (aq) o BaSO_4 (s)\downarrow + 2NaCl (aq)$$

3 MARKS | CBSE 2020, 2015

Define corrosion and rancidity. State two practical methods to prevent corrosion of iron.

Answer

Corrosion: The slow, gradual deterioration of metals due to chemical action of moisture, air, and acids (e.g., Rusting of iron: $Fe_2O_3 \cdot xH_2O$).
Rancidity: Aerial oxidation of fats and oils in food leading to unpleasant smell and taste.
Prevention methods for iron: (1) Galvanisation (coating with zinc), (2) Painting/oiling/greasing, (3) Alloying (e.g., Stainless steel).

5 MARKS | CBSE 2024, 2019

Write balanced chemical equations with state symbols and identify the type of reaction for each:
(a) Burning of natural gas
(b) Heating ferrous sulphate crystals
(c) Reaction of barium chloride with sodium sulphate
(d) Electrolysis of acidified water
(e) Slaking of quicklime

Answer

(a) $CH_4 (g) + 2O_2 (g) o CO_2 (g) + 2H_2O (g) + Heat$ $\implies$ Exothermic / Combustion Reaction

(b) $2FeSO_4 (s) \xr→{\Delta} Fe_2O_3 (s) + SO_2 (g) + SO_3 (g)$ $\implies$ Thermal Decomposition Reaction

(c) $BaCl_2 (aq) + Na_2SO_4 (aq) o BaSO_4 (s)\downarrow + 2NaCl (aq)$ $\implies$ Precipitation / Double Displacement Reaction

(d) $2H_2O (l) \xr→{Electricity} 2H_2 (g) + O_2 (g)$ $\implies$ Electrolytic Decomposition Reaction ($2:1$ volume ratio)

(e) $CaO (s) + H_2O (l) o Ca(OH)_2 (aq) + Heat$ $\implies$ Combination / Exothermic Reaction

Competency-Based Questions

CBSE Board practice items with step-by-step solutions

SECTION 1

Learning Objective Practice Items

Topic Focus

Compare the characteristics of initial & final substances in order to check whether the change is physical or chemical

CBQ 1 • Physical vs Chemical Change

A student poured 100 mL of water in a bottle and added 40 mL vinegar to it. A balloon was filled with 20 g baking soda and was fixed at the mouth of the bottle. Slowly the shape of the balloon changed. The student claims that a chemical change happened when the two substances were mixed. Is the claim made by the student correct?

(a) Yes, as a new substance was formed in the form of a gas.
(b) Yes, as the mass remains the same throughout the experiment.
(c) No, as the formation of bubbles in the mixture shows a physical change.
(d) No, as the change in the shape and size of the balloon shows a physical change.
Correct Answer: (a)

Yes, as a new substance was formed in the form of a gas.

When baking soda (sodium hydrogen carbonate, $\text{NaHCO}_3$) reacts with vinegar (dilute acetic acid, $\text{CH}_3\text{COOH}$), a brisk effervescence occurs releasing carbon dioxide gas ($\text{CO}_2$), which inflates the balloon. The formation of a chemically new gaseous substance with entirely different properties confirms a chemical change.

$$\text{CH}_3\text{COOH} (aq) + \text{NaHCO}_3 (s) \rightarrow \text{CH}_3\text{COONa} (aq) + \text{H}_2\text{O} (l) + \text{CO}_2 (g) \uparrow$$
CBQ 2 • Physical vs Chemical Change

A student makes a list of some activities he observes one day:
1. Baking a cake in an oven
2. Cutting an apple pie into slices
3. Crushing the can after drinking a soda
4. Carving a wooden log to make a stand
Which activity can the student classify as a chemical change?

(a) Activity 1, as the properties of the substances in the mixture change.
(b) Activity 2, as the physical state of the apple pie changes when cut.
(c) Activity 3, as the shape of the can changes.
(d) Activity 4, as the shape and size of the wooden log changes.
Correct Answer: (a)

Activity 1, as the properties of the substances in the mixture change.

Baking involves endothermic chemical reactions among flour, leavening agents, and sugar that create completely new chemical compounds with irreversible texture, taste, and molecular composition. Slicing pie, crushing a can, and carving wood merely alter physical dimensions without altering chemical identity (physical changes).

Topic Focus

Relate the substances taking part in the chemical reaction & substances formed in the chemical reaction in order to classify them as reactants & products

CBQ 3 • Reactants & Products

Sodium and chlorine are reacted and as a result, sodium chloride is formed which is also called table salt. What option gives the reactants and products of the reaction?

(a) reactants - sodium; products - chlorine
(b) reactants - sodium and table salt; products - chlorine
(c) reactants - table salt; products - sodium and chlorine
(d) reactants - sodium and chlorine; products - sodium chloride
Correct Answer: (d)

reactants - sodium and chlorine; products - sodium chloride

Substances that take part and undergo chemical transformation on the left-hand side of the reaction arrow are reactants ($\text{Na}$ and $\text{Cl}_2$), while the resulting substance formed on the right-hand side is the product ($\text{NaCl}$).

CBQ 4 • Reactants & Products

The image shows some chemical reactions:
$$\text{H} + \text{Cl} \longrightarrow \text{HCl}$$
$$2\text{H} + \text{O}_2 \longrightarrow 2\text{H}_2\text{O}$$
Which option identifies the reactants and products of the reactions?

(a) Reactants: $\text{H}$, $\text{Cl}$, and $\text{HCl}$; Products: $2\text{H}$, $\text{O}_2$, and $\text{H}_2\text{O}$
(b) Reactants: $\text{HCl}$ and $2\text{H}_2\text{O}$; Products: $\text{H}$, $\text{Cl}$, $2\text{H}$, and $\text{O}_2$
(c) Reactants: $\text{H}$, $\text{Cl}$, $2\text{H}$, and $\text{O}_2$; Products: $\text{HCl}$ and $2\text{H}_2\text{O}$
(d) Reactants: $2\text{H}$, $\text{O}_2$, and $\text{H}_2\text{O}$; Products: $\text{H}$, $\text{Cl}$, and $\text{HCl}$
Correct Answer: (c)

Reactants: $\text{H}$, $\text{Cl}$, $2\text{H}$, and $\text{O}_2$; Products: $\text{HCl}$ and $2\text{H}_2\text{O}$

All chemical entities written to the left of the transformation arrow are reactants; all entities produced to the right of the arrow are products.

Topic Focus

Use chemical symbols & chemical formulae correctly in order to acquire the skill of writing chemical equations

CBQ 5 • Formulae & Equation Writing

A student performs an experiment to form aluminium chloride from aluminium and chlorine. Which option gives the chemical equation of the reaction?

(a) $\text{Al} + \text{Cl}_2 \rightarrow \text{AlCl}_2$
(b) $2\text{Al} + \text{Cl}_2 \rightarrow 2\text{AlCl}$
(c) $2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3$
(d) $3\text{Al} + 3\text{Cl}_2 \rightarrow 3\text{AlCl}_3$
Correct Answer: (c)

$2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3$

Aluminium has a valency of $+3$ ($\text{Al}^{3+}$) and chlorine has a valency of $-1$ ($\text{Cl}^-$), so the stable molecular formula of aluminium chloride is $\text{AlCl}_3$. Balancing aluminium metal with diatomic chlorine gas requires $2\text{Al} + 3\text{Cl}_2 \rightarrow 2\text{AlCl}_3$.

CBQ 6 • Formulae & Equation Writing

A researcher adds barium hydroxide to hydrochloric acid to form a white-colored barium chloride. Which option gives the balanced chemical equation of the reaction?

(a) $\text{HCl} + \text{Ba(OH)}_2 \rightarrow \text{BaCl}_2 + 2\text{HOH}$
(b) $2\text{HCl} + \text{Ba(OH)}_2 \rightarrow \text{BaCl}_2 + 2\text{HOH}$
(c) $2\text{HCl} + \text{Ba(OH)}_2 \rightarrow \text{BaH}_2 + 2\text{HCl} + \text{O}_2$
(d) $\text{HCl} + 2\text{Ba(OH)} \rightarrow 2\text{BaCl}_2 + 2\text{HOH} + \text{O}_2$
Correct Answer: (b)

$2\text{HCl} + \text{Ba(OH)}_2 \rightarrow \text{BaCl}_2 + 2\text{HOH}$ (or $2\text{H}_2\text{O}$)

Barium hydroxide ($\text{Ba(OH)}_2$, base) neutralizes hydrochloric acid ($\text{HCl}$, acid) to yield barium chloride salt ($\text{BaCl}_2$) and water ($\text{H}_2\text{O}$). Since barium ions ($\text{Ba}^{2+}$) require two chloride ions ($\text{Cl}^-$), $2$ molecules of $\text{HCl}$ must react per formula unit of $\text{Ba(OH)}_2$.

Topic Focus

Apply Law of Conservation of Mass in order to balance chemical equations

CBQ 7 • Conservation of Mass

A student writes a balanced chemical equation:
$$\text{Pb}(s) + \text{CuCl}_2(aq) \rightarrow \text{PbCl}_2(aq) + \text{Cu}(s)$$
Which option gives the number of elements on the LHS and RHS of the chemical equation?

(a) Pb: 1 (LHS), 1 (RHS); Cu: 1 (LHS), 1 (RHS); Cl: 1/2 (LHS), 1/2 (RHS)
(b) Pb: 1 (LHS), 1 (RHS); Cu: 1 (LHS), 1 (RHS); Cl: 1 (LHS), 1 (RHS)
(c) Pb: 1 (LHS), 1 (RHS); Cu: 1/2 (LHS), 1/2 (RHS); Cl: 2 (LHS), 2 (RHS)
(d) Pb: 1 (LHS), 1 (RHS); Cu: 1 (LHS), 1 (RHS); Cl: 2 (LHS), 2 (RHS)
Correct Answer: (d)

Pb: 1 (LHS), 1 (RHS); Cu: 1 (LHS), 1 (RHS); Cl: 2 (LHS), 2 (RHS)

By atom counting: LHS has $1\text{ Pb}$, $1\text{ Cu}$, and $2\text{ Cl}$. RHS has $1\text{ Pb}$, $1\text{ Cu}$, and $2\text{ Cl}$. The total number of atoms of each element remains strictly conserved across the chemical change.

CBQ 8 • Conservation of Mass

The image shows a balanced chemical equation of the reaction between sodium and chlorine to form sodium chloride:
$$2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}$$
Which option shows the number of atoms on both sides of the reaction?

(a) Na: 2 (LHS), 2 (RHS); Cl: 1/2 (LHS), 1/2 (RHS)
(b) Na: 2 (LHS), 2 (RHS); Cl: 2 (LHS), 2 (RHS)
(c) Na: 2 (LHS), 2 (RHS); Cl: 1 (LHS), 1 (RHS)
(d) Na: 1 (LHS), 1 (RHS); Cl: 2 (LHS), 2 (RHS)
Correct Answer: (b)

Na: 2 (LHS), 2 (RHS); Cl: 2 (LHS), 2 (RHS)

LHS contains $2$ atoms of elemental $\text{Na}$ and $1$ diatomic molecule of $\text{Cl}_2$ ($2$ atoms of $\text{Cl}$). RHS contains $2$ formula units of $\text{NaCl}$ ($2$ atoms of $\text{Na}$ and $2$ atoms of $\text{Cl}$).

Topic Focus

Categorize the given reactions as (combination/decomposition) based on the reactants & products of a chemical reaction

CBQ 9 • Combination vs Decomposition

A student writes a chemical equation of the reaction between carbon monoxide and hydrogen:
$$\text{CO} + 2\text{H}_2 \rightarrow \text{CH}_3\text{OH}$$
How can the reaction be classified?

(a) The reaction is an example of a combination reaction as a compound separates into two compounds.
(b) The reaction is an example of a decomposition reaction as a compound dissociates into two compounds.
(c) The reaction is an example of a combination reaction as two compounds react to form a single compound.
(d) The reaction is an example of a decomposition reaction as two compounds react to form a single compound.
Correct Answer: (c)

The reaction is an example of a combination reaction as two compounds react to form a single compound.

Two reactant species (carbon monoxide gas and hydrogen gas) unite chemically under pressure and catalyst to yield one single product (liquid methanol, $\text{CH}_3\text{OH}$). Hence, it is a combination reaction.

CBQ 10 • Combination vs Decomposition

A student learns that some products are formed as a result of combining two compounds while some compounds are formed as a result of dissociation of two compounds. The image shows two reactions:
Reaction P: $\text{CaO} + \text{SO}_2 \rightarrow \text{CaSO}_3$
Reaction Q: $\text{ZnCO}_3 \rightarrow \text{ZnO} + \text{CO}_2$
Which reaction is an example of a combination reaction and a decomposition reaction?

(a) Both the reactions are examples of combination reaction
(b) Both the reactions are examples of a decomposition reaction
(c) Reaction P is an example of a combination reaction while reaction Q is an example of a decomposition reaction
(d) P is an example of a decomposition reaction while reaction Q is an example of a combination reaction
Correct Answer: (c)

Reaction P is an example of a combination reaction while reaction Q is an example of a decomposition reaction

In reaction P, two separate compounds ($\text{CaO} + \text{SO}_2$) combine into a single compound ($\text{CaSO}_3$). In reaction Q, a single reactant compound (zinc carbonate, $\text{ZnCO}_3$) breaks down upon heating into two simpler compounds ($\text{ZnO} + \text{CO}_2$).

Topic Focus

Classify the given reaction as displacement or double displacement based on the type of reactants used & products formed

CBQ 11 • Displacement Reactions

A student adds lead and silver to two different test tubes containing an equal amount of copper sulphate solution. The student observes that the color of the solution in the test tube with lead changes. What explains the change in the colour of the solution?

(a) A displacement reaction takes place as lead replaces copper from the solution.
(b) A combination reaction takes place as lead combines with sulphate in the solution.
(c) A decomposition reaction takes place as copper dissociates from sulphate in the solution.
(d) A double displacement reaction takes place as copper dissociates from sulphate and lead combines with sulphate in the solution.
Correct Answer: (a)

A displacement reaction takes place as lead replaces copper from the solution.

In the metal reactivity series, lead ($\text{Pb}$) is more reactive than copper ($\text{Cu}$), so lead displaces copper from $\text{CuSO}_4$, causing the blue colour of the solution to fade and depositing reddish-brown copper. Silver ($\text{Ag}$) is less reactive than copper, giving no reaction.

$$\text{Pb} (s) + \text{CuSO}_4 (aq) \rightarrow \text{PbSO}_4 (aq) + \text{Cu} (s)$$
CBQ 12 • Double Displacement Reactions

The chemical reaction between potassium chloride and silver nitrate is given by the chemical equation:
$$\text{AgNO}_3 + \text{KCl} \rightarrow \text{AgCl} + \text{KNO}_3$$
What can be inferred from the chemical equation?

(a) Silver nitrate and potassium undergo a decomposition reaction to form silver chloride and potassium nitrate
(b) Silver nitrate and potassium undergo a displacement reaction to form silver chloride and potassium nitrate
(c) Silver nitrate and potassium undergo a combination reaction to form silver chloride and potassium nitrate
(d) Silver nitrate and potassium undergo double displacement reaction to form silver chloride and potassium nitrate
Correct Answer: (d)

Silver nitrate and potassium undergo double displacement reaction to form silver chloride and potassium nitrate

A mutual exchange of ions takes place between the two ionic reactants: $\text{Ag}^+$ pairs with $\text{Cl}^-$ to precipitate insoluble white $\text{AgCl}$, while $\text{K}^+$ pairs with $\text{NO}_3^-$ to remain in solution as $\text{KNO}_3$. This is a classic double displacement (precipitation) reaction.

Topic Focus

Predict the reaction as Oxidation or Reduction based on the addition/removal of oxygen/hydrogen/electrons to the reactants to form products

CBQ 13 • Redox & Electron Transfer

The image shows a reaction between zinc and hydrogen:
$$\text{Zn} + 2\text{H}^+ \rightarrow \text{Zn}^{2+} + \text{H}_2$$
Which option shows oxidation?

(a) $\text{Zn} \rightarrow \text{Zn}^{2+}$
(b) $2\text{H}^+ \rightarrow \text{H}_2$
(c) $\text{Zn}^{2+} \rightarrow \text{Zn}$
(d) $\text{H}_2 \rightarrow 2\text{H}^+$
Correct Answer: (a)

$\text{Zn} \rightarrow \text{Zn}^{2+}$

Oxidation is defined in electronic theory as the loss of electrons (increase in oxidation state). Neutral zinc metal ($\text{Zn}^0$) loses two electrons to form $\text{Zn}^{2+}$, which is an oxidation half-reaction: $\text{Zn} \rightarrow \text{Zn}^{2+} + 2e^-$. Conversely, $2\text{H}^+$ gains two electrons to form $\text{H}_2$ (reduction).

CBQ 14 • Redox Identification

The image shows a reaction between iron oxide and hydrogen:
$$\text{Fe}_3\text{O}_4 + 4\text{H}_2 \longrightarrow 3\text{Fe} + 4\text{H}_2\text{O}$$
Which option shows the compounds undergoing oxidation and reduction?

(a) Oxidation: $4\text{H}_2$; Reduction: $\text{Fe}_3\text{O}_4$
(b) Oxidation: $3\text{Fe}$; Reduction: $4\text{H}_2$
(c) Oxidation: $\text{Fe}_3\text{O}_4$; Reduction: $4\text{H}_2\text{O}$
(d) Oxidation: $4\text{H}_2\text{O}$; Reduction: $\text{Fe}_3\text{O}_4$
Correct Answer: (a)

Oxidation: $4\text{H}_2$; Reduction: $\text{Fe}_3\text{O}_4$

Hydrogen ($\text{H}_2$) gains oxygen to form $\text{H}_2\text{O}$, so $\text{H}_2$ undergoes oxidation. Magnetic iron oxide ($\text{Fe}_3\text{O}_4$) loses oxygen to form elemental $\text{Fe}$, so $\text{Fe}_3\text{O}_4$ undergoes reduction.

Topic Focus

Observe colour change in iron, copper and silver articles over time in order to outline the effects of corrosion in our surroundings

CBQ 15 • Corrosion of Iron

A student notices that a new hammer made of iron is shiny while an old one kept in the toolbox for long has a reddish-brown powder deposit over it. What does the change in colour of the hammer indicate?

(a) Effect of moisture on metals
(b) Iron hammer turns brown after some time
(c) Effects of kept in a box for a longer duration
(d) Iron changes colour when kept with other tools
Correct Answer: (a)

Effect of moisture on metals

Iron articles slowly react with atmospheric oxygen in the presence of moisture (water vapour) to form hydrated ferric oxide (rust, $\text{Fe}_2\text{O}_3 \cdot x\text{H}_2\text{O}$), which is reddish-brown and flaky. This demonstrates the corrosive effect of air and moisture on metals.

CBQ 16 • Corrosion of Silver

A student notices that her silver jewellery turned dull and had a gray-black film over it after wearing for a few months. What results in the change in colour of the silver metal?

(a) Dust deposits over the jewellery which changes its colour
(b) The jewellery comes in contact with air, moisture, and acids and corrodes
(c) The polish over the jewellery was removed after wearing for a few months
(d) Silver breaks due to wear and tear and turns its colour changes due to rusting
Correct Answer: (b)

The jewellery comes in contact with air, moisture, and acids and corrodes

Silver reacts with trace sulphur compounds (such as hydrogen sulphide, $\text{H}_2\text{S}$) present in air to form a thin black coating of silver sulphide ($\text{Ag}_2\text{S}$):

$$2\text{Ag} (s) + \text{H}_2\text{S} (g) \rightarrow \text{Ag}_2\text{S} (s) [\text{Black}] + \text{H}_2 (g)$$

Topic Focus

Detect changes in smell, colour, taste of food items over time, in order to explain effects of oxidation on food items

CBQ 17 • Prevention of Rancidity

A student learns that food companies fill bags of chips with nitrogen gas. What is the purpose of packing it with nitrogen?

(a) It prevents rancidity of chips
(b) It keeps the mosquitoes away from chips
(c) It keeps the chips dry if the pack falls in water
(d) Prevents chips from spilling out when the pack is opened
Correct Answer: (a)

It prevents rancidity of chips

Potato chips contain fats and oils. When exposed to oxygen in air, fats undergo aerial oxidation into foul-smelling, bad-tasting volatile substances (a process known as rancidity). Flushing sealed packaging with unreactive, inert nitrogen gas ($\text{N}_2$) displaces oxygen and prevents oxidation.

CBQ 18 • Oxidation & Spoilage

A student notices that the bread kept out has a green coloured coating over it after a few days. What explains the reason for the student's observation?

(a) The oils in the bread oxidises and causes rancidity
(b) Bread comes in contact with atmospheric moisture and corrodes
(c) The oils in the bread reduces and cause the change in the colour of the bread
(d) Comes in contact with the atmospheric nitrogen and a layer deposit over it
Correct Answer: (a)

The oils in the bread oxidises and causes rancidity

Food items containing moisture and fats deteriorate through aerobic microbiological action and oxidative rancidity, altering the surface texture and color (development of fungal spores and chemical degradation of organic compounds).

SECTION 2

Case Study & Contextual Questions

Context for Questions 1 & 2

When steam is passed through red hot iron, iron oxide and hydrogen gas is formed. The balanced equation for the reaction is shown below:
$$3\text{Fe}(s) + 4\text{H}_2\text{O}(g) \rightarrow \text{Fe}_3\text{O}_4(s) + 4\text{H}_2(g)$$

CBQ 19 • SAS21S100101

Is heating iron to red hot a physical or a chemical change? Explain your answer.

Answer: Physical change

Physical change.

Explanation: Heating iron until it glows red hot only changes its temperature and visual appearance (thermal radiation emission/state of glow) without changing its chemical identity or composition. When cooled back to room temperature, it returns to ordinary metallic iron with no new chemical substance formed.

CBQ 20 • SAS21S100102

What is true for the balanced chemical equation shown above ($$3\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2$$)?

A. Four atoms of water combine with iron to form four atoms of hydrogen.
B. Three atoms of iron combine with water to form four atoms of hydrogen.
C. Four molecules of water combine with iron to form an atom of iron oxide.
D. Three atoms of iron combine with water to form one molecule of iron oxide.
Correct Answer: D

Three atoms of iron combine with water to form one molecule of iron oxide.

Stoichiometric analysis: 3 atoms (or moles) of iron ($\text{Fe}$) react with 4 molecules of water vapor ($\text{H}_2\text{O}$) to form 1 formula unit/molecule of magnetic iron oxide ($\text{Fe}_3\text{O}_4$) and 4 molecules (8 atoms) of dihydrogen gas ($\text{H}_2$). Water is a molecular substance, not atomic, eliminating options A and B; $\text{Fe}_3\text{O}_4$ is a compound molecule, eliminating option C.

Context for Questions 3 & 4

Cellular respiration is a chemical process by which cells convert glucose to energy:
$$\text{C}_6\text{H}_{12}\text{O}_6(aq) + 6\text{O}_2(g) \rightarrow 6\text{CO}_2(g) + 6\text{H}_2\text{O}(l) + \text{Energy}$$

CBQ 21 • SAS21S100103

In the above reaction, which substance is oxidised?

Answer: Glucose (\text{C}_6\text{H}_{12}\text{O}_6)

Glucose ($\text{C}_6\text{H}_{12}\text{O}_6$) is oxidised.

Explanation: In cellular respiration, glucose loses hydrogen and gains bonds with electronegative oxygen to form carbon dioxide ($\text{CO}_2$). The removal of hydrogen from carbon and addition of oxygen constitutes oxidation. Concurrently, molecular oxygen ($\text{O}_2$) is reduced to water ($\text{H}_2\text{O}$) by the addition of hydrogen.

CBQ 22 • SAS21S100104

Carbon dioxide and water are the two new substances formed during cellular respiration. What are they known as?

A. Reactants
B. Mixtures
C. Catalysts
D. Products
Correct Answer: D

Products

Explanation: The substances synthesized/formed as a result of a chemical transformation are located on the right side of the reaction arrow and are called products. The starting materials ($ \text{C}_6\text{H}_{12}\text{O}_6 $ and $ \text{O}_2 $) are reactants.

Context for Questions 5 to 7

A piece of magnesium ribbon is added to a flask containing dilute hydrochloric acid. Hydrogen gas is formed and collected in a measuring cylinder over time to track the reaction rate:
$$\text{Mg}(s) + 2\text{HCl}(aq) \rightarrow \text{MgCl}_2(aq) + \text{H}_2(g)$$

CBQ 23 • SAS21S100105

At what time is the reaction rate the fastest in the flask?

A. At 1 minute
B. At 3 minutes
C. At 4 minutes
D. At 6 minutes
Correct Answer: A

At 1 minute

Reaction Kinetics explanation: The reaction rate is highest at the very start ($t = 0$ to $1$ minute) because the concentrations of the reactants ($[\text{HCl}]$) and available surface area of unreacted magnesium are at their maximum. As the reaction proceeds, reactants are consumed, so the collision frequency decreases and the slope of the gas-volume curve flattens over time.

CBQ 24 • SAS21S100106

The reaction is repeated with magnesium powder in place of magnesium ribbon under the same conditions. Will the reaction rate increase or decrease? Explain your answer with reference to the volume of hydrogen formed in the flask at 2 minutes.

Answer: Reaction rate will increase

Reaction rate will increase.

Explanation & Volume at 2 minutes:

  • Magnesium powder has a vastly greater specific surface area compared to a single strip of ribbon of identical mass.
  • A higher surface area provides far more exposed magnesium atoms for acid particles ($ \text{H}^+ $ ions) to collide with per second, markedly accelerating the reaction rate.
  • Therefore, at 2 minutes, a noticeably greater volume of $\text{H}_2$ gas will have already been produced in the measuring cylinder compared to the ribbon experiment.
CBQ 25 • SAS21S100107

Which of these could increase the rate of reaction in the flask? (Answer 'Yes' or 'No' for each):
1. Adding more acid to the flask (at same concentration)
2. Heating the acid in the flask
3. Using a higher concentration of acid

Answer: 1. No | 2. Yes | 3. Yes

Correct evaluations:

  1. Adding more acid to the flask: No — Increasing the volume without increasing concentration keeps collision frequency per unit area unchanged (assuming acid was already in excess).
  2. Heating the acid in the flask: Yes — Higher temperature increases kinetic energy of reactant particles, boosting collision frequency and the fraction of collisions surpassing activation energy.
  3. Using a higher concentration of acid: Yes — Greater number of $\text{H}^+$ ions per unit volume leads to higher collision frequency with magnesium surface.
CBQ 26 • SAS21S100108

Magnesium reacts with hydrochloric acid to form magnesium chloride and hydrogen gas. Write a balanced chemical equation to show the reaction with state symbols.

Balanced Equation: \text{Mg}(s) + 2\text{HCl}(aq) \rightarrow \text{MgCl}_2(aq) + \text{H}_2(g)

Balanced Chemical Equation:

$$\text{Mg}(s) + 2\text{HCl}(aq) \longrightarrow \text{MgCl}_2(aq) + \text{H}_2(g)$$

Balancing steps: Magnesium has a valency of $+2$ and forms magnesium chloride $\text{MgCl}_2$. Two hydrogen atoms form diatomic gas $\text{H}_2$. Thus, 2 molecules of hydrochloric acid $\text{HCl}$ are required for every 1 atom of magnesium ribbon, conserving all mass.

CBQ 27 • SAS21S100109

Which of these is an example of a decomposition reaction?

A. Melting of glaciers
B. Rusting of old bridges
C. Rotting of fruits and vegetables
D. Absorption of carbon dioxide by oceans
Correct Answer: C

Rotting of fruits and vegetables

Explanation:

  • Rotting/decay: Microorganisms digest and decompose complex organic compounds (polysaccharides, proteins) in dead plant matter into simpler compounds (ammonia, $\text{CO}_2$, $\text{H}_2\text{O}$), which is a microbiological decomposition reaction.
  • Melting of glaciers is a physical phase change (solid to liquid).
  • Rusting is an oxidation/combination reaction ($4\text{Fe} + 3\text{O}_2 + 2x\text{H}_2\text{O} \rightarrow 2\text{Fe}_2\text{O}_3\cdot x\text{H}_2\text{O}$).
  • Absorption of $\text{CO}_2$ is dissolution/formation of carbonic acid (combination reaction).
CBQ 28 • SAS21S100110

Methane gas released from waste water treatment plants can be used as a source of fuel. Which chemical equation represents combustion of methane to produce heat energy?

A. $\text{CH}_4 + \text{CO}_2 \rightarrow 2\text{O}_2 + 2\text{H}_2\text{O}$
B. $\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}$
C. $2\text{O}_2 + 2\text{H}_2\text{O} \rightarrow \text{CO}_2 + \text{CH}_4$
D. $\text{CO}_2 + 2\text{O}_2 \rightarrow \text{CH}_4 + 2\text{H}_2\text{O}$
Correct Answer: B

$$\text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O}$$

Combustion reaction: Methane (natural gas fuel) undergoes exothermic oxidation with atmospheric oxygen to yield carbon dioxide gas, water vapor, and liberating substantial thermal energy ($\Delta H < 0$). Mass conservation: 1 C, 4 H, 4 O on both sides.

SECTION 3

CBSE Item Bank Questions

CBQ 29 • 1 mark

Methane gas is burnt in air. State whether the reaction is exothermic or endothermic.

Answer: Exothermic reaction

Exothermic reaction.

Reason: When methane burns in the presence of oxygen, bonds in carbon dioxide and water are formed, releasing large amounts of heat and light energy into the surroundings: $$\text{CH}_4(g) + 2\text{O}_2(g) \longrightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(g) + \text{Heat}$$

CBQ 30 • 1 mark

Which of the following reactions is exothermic?

A. Quick lime is dissolved in water to produce slaked lime.
B. Calcium carbonate is heated to produce carbon dioxide gas and quick lime.
C. Lead nitrate is heated to produce lead oxide, nitrogen dioxide and oxygen.
D. Mercuric oxide is heated to produce mercury and oxygen.
Correct Answer: A

Quick lime is dissolved in water to produce slaked lime.

Explanation: Reaction A (slaking of lime) releases immense thermal energy, causing the water to boil violently ($$\text{CaO}(s) + \text{H}_2\text{O}(l) \rightarrow \text{Ca(OH)}_2(aq) + \text{Heat}$$). Reactions B, C, and D are thermal decomposition reactions that absorb heat energy from the surroundings, making them endothermic.

CBQ 31 • 3 marks

The reaction between magnesium and oxygen produces magnesium oxide. Energy is released as heat and light during the reaction. Complete and balance the symbol equation to show this reaction. Include the state symbols.
$$\text{Mg} + \text{O}_2 \rightarrow$$

Balanced Equation: 2\text{Mg}(s) + \text{O}_2(g) \rightarrow 2\text{MgO}(s)

Complete balanced symbol equation:

$$2\text{Mg}(s) + \text{O}_2(g) \longrightarrow 2\text{MgO}(s)$$

Marking Scheme Breakdown:

  • 1 mark: Correct formula for product ($\text{MgO}$).
  • 1 mark: Balanced coefficients ($2\text{Mg}$ and $2\text{MgO}$).
  • 1 mark: Correct physical state symbols: $(s)$ for $\text{Mg}$, $(g)$ for $\text{O}_2$, and $(s)$ for $\text{MgO}$.
CBQ 32 • 1 mark

Explain why the reaction between magnesium and oxygen can be described as a combination reaction.

Explanation: Two reactants combine to form a single product

Explanation:

It is classified as a combination reaction because two distinct starting reactants (magnesium metal, an element, and oxygen gas, an element) combine chemically to yield only a single chemical product, magnesium oxide ($\text{MgO}$).

CBQ 33 • 1 mark

Explain why the reaction between magnesium and oxygen can be described as an oxidation reaction.

Explanation: Magnesium gains oxygen / loses electrons

Explanation:

The reaction is an oxidation reaction because magnesium gains oxygen to form magnesium oxide ($\text{MgO}$). In terms of electronic concept, each neutral magnesium atom loses two electrons ($\text{Mg} \rightarrow \text{Mg}^{2+} + 2e^-$), which defines oxidation.

CBQ 34 • 1 mark

Explain why the reaction between magnesium and oxygen can be described as an exothermic reaction.

Explanation: Heat and light energy are released to the surroundings

Explanation:

The reaction releases energy into the surroundings in the form of intense heat and a dazzling white light; any reaction that releases thermal energy to the surroundings is termed an exothermic reaction.

CBQ 35 • 2 marks

Suggest why the surface of the magnesium ribbon must be cleaned with sandpaper before the ribbon is used.

Reason: To remove the protective basic magnesium oxide/carbonate coating

Key reasons:

  1. Magnesium is a reactive metal that slowly reacts with atmospheric oxygen and moisture at room temperature to form a tough, unreactive protective layer of basic magnesium oxide/carbonate ($\text{MgO} / \text{MgCO}_3$) on its surface.
  2. Cleaning the ribbon with sandpaper strips off this dull inert coating so that pure underlying metallic magnesium is directly exposed to flame and oxygen, allowing it to ignite smoothly.
CBQ 36 • 3 marks

Describe three other precautions that must be taken when burning magnesium.

Precautions: Tongs, safety goggles/tinted glass, keep away from eyes/face

Three essential lab precautions:

  1. Hold with crucible tongs: Never hold the burning magnesium ribbon with bare hands or forceps that conduct heat; hold it firmly using metal crucible tongs over a watch glass.
  2. Wear safety goggles / UV eye protection: Do not look directly at the dazzling, brilliant white flame, as the intense ultraviolet emission can injure the retina.
  3. Keep at a safe distance from face and body: Hold the burning ribbon away from clothing and face, placing a watch glass below to safely collect hot falling white ash.
CBQ 37 • 2 marks

Magnesium oxide dissolves slightly in water to produce an aqueous solution. Suggest the pH of the solution and explain your answer.

Answer: pH > 7 (approx 9-10), basic/alkaline solution

Suggested pH & Explanation:

pH: Approximately 9 to 10 (greater than 7).

Explanation: Magnesium oxide is a metallic oxide, and basic in nature. When mixed with water, it sparingly dissolves to form magnesium hydroxide, a weak base/alkali: $$\text{MgO}(s) + \text{H}_2\text{O}(l) \longrightarrow \text{Mg(OH)}_2(aq)$$ This releases hydroxide ions ($\text{OH}^-$) into the solution, turning red litmus paper blue and producing an alkaline $\text{pH} > 7$.

CBQ 38 • 1 mark

A chemical reaction in which two or more substances combine to form a single product is:

A. a decomposition reaction
B. a combination reaction
C. a displacement reaction
D. an exothermic reaction
Correct Answer: B

a combination reaction

Definition: Reactions in which two or more simple reactants (elements or compounds) combine chemically to produce a single chemical compound ($A + B \rightarrow AB$) are known as combination (or synthesis) reactions.

CBQ 39 • 4 marks

Decomposition is a type of chemical reaction. Using water as an example, state and explain what happens in electrolytic decomposition.

Explanation: Water splits into hydrogen and oxygen gases in 2:1 volume ratio via electric current

Electrolytic decomposition of water:

  • Definition: Electrolytic decomposition is a chemical reaction where a chemical compound is split into simpler constituent substances by passing an electric current through its molten or aqueous state.
  • Chemical Equation: $$2\text{H}_2\text{O}(l) \xrightarrow{\text{Electric current}} 2\text{H}_2(g) \uparrow + \text{O}_2(g) \uparrow$$
  • Cathode reaction: Dihydrogen gas ($\text{H}_2$) is liberated at the negative electrode (cathode) by reduction ($2\text{H}^+ + 2e^- \rightarrow \text{H}_2$).
  • Anode reaction: Dioxygen gas ($\text{O}_2$) is liberated at the positive electrode (anode) by oxidation ($2\text{O}^{2-} \rightarrow \text{O}_2 + 4e^-$).
  • Volume Ratio: Since two parts of hydrogen combine with one part of oxygen by volume in water, the volume of $\text{H}_2$ gas collected at the cathode is exactly twice ($2:1$) the volume of $\text{O}_2$ gas collected at the anode.
CBQ 40 • 1 mark

Suggest why pure water does not undergo electrolytic decomposition.

Reason: Pure water is a poor conductor of electricity due to very low ion concentration

Reason: Pure distilled water consists almost entirely of neutral covalent molecules and undergoes negligible self-ionization ($[\text{H}^+] = [\text{OH}^-] = 10^{-7}\text{ M}$). Because it contains virtually no free mobile charge carriers (ions) to conduct electric current, it is an insulator. A few drops of dilute sulfuric acid or an ionic salt must be added to acidulate water and facilitate electrolysis.

CBQ 41 • 1 mark

What type of chemical reaction is shown?
$$4\text{NH}_3 + 5\text{O}_2 \rightarrow 4\text{NO} + 6\text{H}_2\text{O}$$

A. Combination reaction
B. Displacement reaction
C. Double displacement reaction
D. Neutralisation reaction
Correct Answer: B

Displacement reaction (also a Redox reaction)

Explanation: In this reaction, the more electronegative oxygen atoms displace the hydrogen atoms from ammonia ($\text{NH}_3$), binding with nitrogen to form nitric oxide ($\text{NO}$) and with hydrogen to form water ($\text{H}_2\text{O}$). Nitrogen is oxidized (oxidation state $-3 \rightarrow +2$) and oxygen is reduced ($0 \rightarrow -2$). Hence it is classified as a displacement/redox reaction.

CBQ 42 • 2 marks

Calcium oxide reacts vigorously with water. Construct the balanced symbol equation for the reaction between calcium oxide and water with state symbols.

Balanced Equation: \text{CaO}(s) + \text{H}_2\text{O}(l) \rightarrow \text{Ca(OH)}_2(aq) + \text{Heat}

Balanced Symbol Equation:

$$\text{CaO}(s) + \text{H}_2\text{O}(l) \longrightarrow \text{Ca(OH)}_2(aq) + \text{Heat}$$

Marking criteria: 1 mark for correct chemical formulas of calcium oxide ($\text{CaO}$), water ($\text{H}_2\text{O}$), and calcium hydroxide / slaked lime ($\text{Ca(OH)}_2$); 1 mark for stoichiometric balance and state symbols.

CBQ 43 • 1 mark

State and explain the type of reaction between calcium oxide and water.

Type: Combination reaction & Exothermic reaction

Reaction Type: Combination reaction and highly exothermic reaction.

Explanation: Two distinct compounds (calcium oxide and water) react chemically to yield a single compound (calcium hydroxide), satisfying the definition of a combination reaction. In addition, it liberates an enormous quantity of heat energy, raising temperature to boiling levels, making it exothermic.

CBQ 44 • 1 mark

State two precautions you should take when reacting calcium oxide with water.

Precautions: Do not touch beaker with bare hands; add water slowly

Two lab precautions:

  1. Avoid touching the reaction vessel directly: The beaker becomes intensely hot due to vigorous exothermic heat liberation and can cause severe thermal burns.
  2. Add water slowly / wear eye goggles: The vigorous bubbling, steam generation, and spitting of caustic alkaline slaked lime suspension can cause skin and eye irritation.
CBQ 45 • 2 marks

The product of the reaction in question 42 can be used to make calcium carbonate ($\text{CaCO}_3$). Identify the reacting gas and the other product formed.

Reacting Gas: Carbon dioxide (\text{CO}_2) | Other Product: Water (\text{H}_2\text{O})

Identifications:

  • Reacting gas: Carbon dioxide ($\text{CO}_2$).
  • Other product formed: Water ($\text{H}_2\text{O}$).

Chemical Equation: $$\text{Ca(OH)}_2(aq) + \text{CO}_2(g) \longrightarrow \text{CaCO}_3(s) \downarrow + \text{H}_2\text{O}(l)$$ This reaction is used for whitewashing walls, forming a thin, lustrous layer of calcium carbonate after 2 to 3 days, and is also the standard confirmatory test for carbon dioxide (turning lime water milky).

CBQ 46 • 1 mark

Which of the following statement(s) about the given reaction are correct?
$$3\text{Fe} + 4\text{H}_2\text{O} \rightarrow \text{Fe}_3\text{O}_4 + 4\text{H}_2$$
1. Iron is oxidised
2. Water is oxidised
3. Water is reducing agent
4. Water is oxidising agent

A. 1 and 4
B. 2 and 3
C. 1 and 3
D. 1 only
Correct Answer: A

1 and 4 (Iron is oxidised; Water is oxidising agent)

Redox Analysis:

  • Iron ($\text{Fe}$): Gains oxygen to form $\text{Fe}_3\text{O}_4$. Hence, Iron is oxidised (Statement 1 is correct).
  • Water ($\text{H}_2\text{O}$): Loses oxygen to become hydrogen gas ($\text{H}_2$). Hence, water is reduced (Statement 2 is incorrect).
  • Because water provides oxygen and causes the oxidation of iron while being itself reduced, water acts as the oxidising agent (Statement 4 is correct; Statement 3 is incorrect).
  • Therefore, statements 1 and 4 are correct.

Rapid Revision

Read this before entering the exam hall

⚡ Definitions

  • Chemical reaction → chemical change producing new substances.
  • Combination → many reactants, one product.
  • Decomposition → one reactant, many products.
  • Displacement → one element displaces another.
  • Double displacement → exchange of ions/groups.
  • Oxidation → gain O / loss H.
  • Reduction → loss O / gain H.
  • Corrosion → deterioration of metals by surroundings.
  • Rancidity → oxidation of fats/oils.

🧪 Must-Know Equations

  • 2Mg + O₂ → 2MgO
  • CaO + H₂O → Ca(OH)₂ + Heat
  • CaCO₃ → CaO + CO₂
  • 2AgCl → 2Ag + Cl₂
  • Fe + CuSO₄ → FeSO₄ + Cu
  • Na₂SO₄ + BaCl₂ → BaSO₄ + 2NaCl
  • CuO + H₂ → Cu + H₂O
  • C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + Energy

🧠 Mnemonics

  • SCGT → State, Colour, Gas, Temperature
  • EXO → Energy EXits
  • ENDO → Energy ENters
  • OIL RIG → Oxidation Is Loss, Reduction Is Gain
  • A+B→AB → Combination
  • AB→A+B → Decomposition

📋 Quick Exam Checklist

  • Never leave a chemical equation unbalanced.
  • Never change chemical formula subscripts while balancing.
  • Learn the four major reaction types.
  • Remember oxidation/reduction definitions.
  • Remember corrosion and rancidity examples.
  • Write observations when the question asks “what do you observe?”
  • Use state symbols when specifically required.

Chapter Test

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