Home Class 11 Applied Maths Chapter 16: Circle and Parabola

CBSE Applied Maths (2026-27) Unit VII: Coordinate Geometry Weightage: ~5 Marks in Unit

Chapter 16: Circle and Parabola

Analyze circles (standard/general equations, diameter endpoints) and parabolas (focus, directrix, four standard forms, architectural applications).

2 Exercises

CBSE Curriculum Aligned

Interactive Quizzes & Solutions

Chapter Exercises & Topics

Select any exercise to access theory notes, formulas, practice drills, and mini tests.

Exercise 16.1 45 mins

Geometric definition and standard center-radius form: (x-h)^2 + (y-k)^2 = r^2
General second-degree equation of a circle: x^2 + y^2 + 2gx + 2fy + c = 0
Finding center (-g, -f) and radius √(g^2 + f^2 - c)
Equation of a circle when end-points of a diameter are given: (x-x1)(x-x2) + (y-y1)(y-y2) = 0

Study Exercise Mini Test

Exercise 16.2 45 mins

Conic section definition (focus, directrix, eccentricity e = 1)
Vertex, focal length (a), axis of symmetry, focal chord, and latus rectum (4a)
Four standard orientations: y^2 = 4ax, y^2 = -4ax, x^2 = 4ay, x^2 = -4ay
Real-world applications (suspension cables, satellite dish reflectors, trajectory paths)

Study Exercise Mini Test

Quick-glance formula revision for examination and numerical problem-solving:

$$(x-h)^2 + (y-k)^2 = r^2$$
$$x^2 + y^2 + 2gx + 2fy + c = 0 \implies \text{Center: } (-g, -f), \; r = \sqrt{g^2 + f^2 - c}$$
$$(x-x_1)(x-x_2) + (y-y_1)(y-y_2) = 0$$
$$y^2 = 4ax: \text{Focus: } (a, 0), \; \text{Directrix: } x = -a, \; \text{LR: } 4a$$
$$y^2 = -4ax: \text{Focus: } (-a, 0), \; \text{Directrix: } x = a$$
$$x^2 = 4ay: \text{Focus: } (0, a), \; \text{Directrix: } y = -a$$
$$x^2 = -4ay: \text{Focus: } (0, -a), \; \text{Directrix: } y = a$$