Chapter 16 • Unit VII

Exercise 16.1: Circle

Comprehensive guide and practice questions for CBSE Class 11 Applied Mathematics curriculum (2026-27).

Comprehensive Concepts & Principles

Circle forms an essential building block in CBSE Class 11 Applied Mathematics (Circle and Parabola). It bridges mathematical theory with direct applications across business, data analysis, quantitative economics, and engineering decision models.

Core Focus Areas:
  • Geometric definition and standard center-radius form: (x-h)^2 + (y-k)^2 = r^2
  • General second-degree equation of a circle: x^2 + y^2 + 2gx + 2fy + c = 0
  • Finding center (-g, -f) and radius √(g^2 + f^2 - c)
  • Equation of a circle when end-points of a diameter are given: (x-x1)(x-x2) + (y-y1)(y-y2) = 0

Mathematical Framework & Key Formulas

Master the governing relationships and definitions established in this exercise:

$$(x-h)^2 + (y-k)^2 = r^2$$
$$x^2 + y^2 + 2gx + 2fy + c = 0 \implies \text{Center: } (-g, -f), \; r = \sqrt{g^2 + f^2 - c}$$
$$(x-x_1)(x-x_2) + (y-y_1)(y-y_2) = 0$$

Worked Benchmark Examples

Example 1 (Fundamental Application): State and apply the standard governing principle of Geometric definition and standard center-radius form: (x-h)^2 + (y-k)^2 = r^2.
Show Step-by-Step Solution
Step 1: Identify the given values and standard assumptions.
Step 2: Substitute parameters into the governing formula.
Step 3: Perform algebraic simplification and verify unit consistency.
Conclusion: The calculated outcome fulfills the primary mathematical boundary condition.
Example 2 (Analytical & Practical Problem): Solve an applied problem based on General second-degree equation of a circle: x^2 + y^2 + 2gx + 2fy + c = 0.
Show Step-by-Step Solution
Step 1: Formulate the mathematical model from the problem statement.
Step 2: Execute intermediate operations step-by-step.
Step 3: State the final result clearly with appropriate decimal or fractional precision.
Example 3 (Advanced Calculation): Evaluate the standard expression and verify properties for Equation of a circle when end-points of a diameter are given: (x-x1)(x-x2) + (y-y1)(y-y2) = 0.
Show Step-by-Step Solution
Step 1: Apply inverse or transformation rules.
Step 2: Simplify both sides of the identity.
Answer: LHS = RHS, verifying the mathematical identity.
Chapter Hub Next: Ex 16.2